3y^2+3(4y^2-2)=

Solution for 3y^2+3(4y^2-2)= equation:

Simplifying
3y2 + 3(4y2 + -2) = 0

Reorder the terms:
3y2 + 3(-2 + 4y2) = 0
3y2 + (-2 * 3 + 4y2 * 3) = 0
3y2 + (-6 + 12y2) = 0

Reorder the terms:
-6 + 3y2 + 12y2 = 0

Combine like terms: 3y2 + 12y2 = 15y2
-6 + 15y2 = 0

Solving
-6 + 15y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 15y2 = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 15y2 = 0 + 6
15y2 = 0 + 6

Combine like terms: 0 + 6 = 6
15y2 = 6

Divide each side by '15'.
y2 = 0.4

Simplifying
y2 = 0.4

Take the square root of each side:
y = {-0.632455532, 0.632455532}